លទ្ធផលស្វែងរក

}_{t=u+T}\int _{2T}^{3T}e^{-pt}f(t)dt{\mid }_{t=u+2T}+...\,} ∫0∞e−ptf(t)dt=∫0Te−ptf(u)du+∫T2Te−p(u+T)f(u+T)du+∫2T3Te−p(u+2T)f(u+2T)du+...{\displaystyle...

{x^{2}-x+3}}}}\,dx\,\!} តាង x2−x+3=x+t⇒x=3−t21+2t{\displaystyle {\sqrt {x^{2}-x+3}}\,=\,x+t\,\Rightarrow x={\frac {3-t^{2}}{1+2t}}\,\!} ខ/ បើ Δ<0 ; c >0 តាង...

{2t}{1+t^{2}}},} sec⁡(φ)=1+t21−t2,{\displaystyle \sec(\varphi )={\frac {1+t^{2}}{1-t^{2}}},}   tan⁡(φ)=2t1−t2,{\displaystyle \tan(\varphi )={\frac {2t}{1-t^{2}}}...